Free Statistics

of Irreproducible Research!

Author's title

Author*The author of this computation has been verified*
R Software Modulerwasp_surveyscores.wasp
Title produced by softwareSurvey Scores
Date of computationTue, 19 Oct 2010 14:33:53 +0000
Cite this page as followsStatistical Computations at FreeStatistics.org, Office for Research Development and Education, URL https://freestatistics.org/blog/index.php?v=date/2010/Oct/19/t1287498770ptgqhzzn2ql0yep.htm/, Retrieved Mon, 29 Apr 2024 07:15:27 +0000
Statistical Computations at FreeStatistics.org, Office for Research Development and Education, URL https://freestatistics.org/blog/index.php?pk=86538, Retrieved Mon, 29 Apr 2024 07:15:27 +0000
QR Codes:

Original text written by user:
IsPrivate?No (this computation is public)
User-defined keywords
Estimated Impact99
Family? (F = Feedback message, R = changed R code, M = changed R Module, P = changed Parameters, D = changed Data)
-     [Survey Scores] [Intrinsic Motivat...] [2010-10-12 11:23:25] [b98453cac15ba1066b407e146608df68]
F   PD    [Survey Scores] [] [2010-10-19 14:33:53] [a7dcbcc9dd9573c89c41df6a7f8b5a0d] [Current]
Feedback Forum
2010-10-20 17:29:01 [] [reply
De student geeft bij deze opdracht als oplossing dat Q2 en Q3 een lage correlatie hebben - maar 0.99 vind ik niet laag deze is nog steeds bijna gelijk aan 1. Dus toch nog een vrij grote correlatie
2010-10-22 12:59:01 [] [reply
Ik denk dat we hier niet mogen spreken van een lage correlatie als deze bijna 1 is.
2010-10-23 10:33:39 [48eb36e2c01435ad7e4ea7854a9d98fe] [reply
Ook hier is de conclusie die de student getrokken heeft niet geheel correct.

De correlatie heeft namelijk te maken met de verhoudingen tussen de drie methoden (mean, (Ps-Ns)/(Ps+Ns) en (Pc-Nc)/(Pc+Nc)). Men ziet - in de tweede tabel - een hoge correlatie tussen deze drie aangezien de waarden allemaal zeer dicht in de buurt van 1 liggen.
Dit betekent dat de drie methodes vergelijkbaar zijn en dat men dus kan werken met het gemiddelde voor verdere berekeningen. Men mag de resultaten van de enquête met andere woorden beschouwen als rekenkundige getallen waarmee men kan rekenen.

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Dataseries X:
7	1	4	5
5	3	5	4
5	4	4	5
5	5	5	6
5	5	5	5
7	7	7	7
7	1	4	7
5	5	6	6
3	2	4	7
6	3	3	6
7	6	5	7
6	4	2	5
5	3	3	3
3	3	3	2
7	6	7	7
5	5	5	5
7	5	5	5
7	5	4	6
7	1	6	7
6	5	6	6
5	3	4	5
7	4	6	7
4	2	3	5
7	3	2	5
7	5	5	6
7	5	5	7
7	5	5	7
3	2	1	2
7	4	5	6
5	6	6	6
7	6	5	7
5	4	6	6
5	6	7	6
4	3	4	4
5	6	5	6
6	3	6	6
7	4	7	7
5	4	2	5
7	7	7	7
7	5	5	6
6	5	5	5
6	4	5	6
7	6	6	7
7	4	5	6
6	4	5	6
6	2	4	6
4	3	2	3
7	6	6	6
5	4	4	4
6	6	6	6
5	3	3	4
3	4	3	3
7	5	7	7
6	2	4	4
6	7	4	7
5	6	5	5
5	5	5	5
7	1	2	4
7	6	6	6
7	6	6	6
6	2	5	7
6	5	6	5
7	5	4	4
7	6	6	7
5	5	4	4
7	4	4	7
6	6	6	6
5	2	4	6
6	6	6	6
5	5	5	5
5	4	5	5
6	2	6	6
6	2	2	5
6	5	6	6
7	6	7	6
6	6	5	5
5	5	5	5
7	5	6	6
7	5	7	7
6	5	5	5
7	5	6	7
6	3	2	2
6	4	5	5
7	3	6	6
6	4	6	7
7	7	7	7
7	5	5	5
5	5	5	5
3	1	1	1
6	4	5	6
6	4	5	5
5	3	4	6
6	5	5	7
6	5	3	6
6	6	6	6
7	5	5	5
6	3	6	6
6	3	4	5
6	4	5	6
7	5	5	6
6	5	6	6
5	3	2	5
5	5	6	5
6	6	6	6
6	6	5	6
6	5	5	5
5	4	6	6
6	4	4	6
4	2	4	1
6	3	6	7
7	6	7	7
7	6	6	6
5	6	3	4
5	5	5	5
7	6	5	6
3	2	2	3
7	6	7	7
5	5	5	6
7	3	5	6
5	5	2	6
3	4	3	5
6	6	6	6
5	5	6	6
4	4	3	3
7	7	7	7
6	2	5	5
7	6	7	6
2	6	4	5
5	4	5	5
6	4	6	6
6	3	4	5
6	6	6	6
2	5	3	5
6	6	3	3
7	6	6	7
4	1	3	3
7	5	7	7
7	4	5	5
6	6	5	6
6	6	5	6
2	5	4	4
7	4	5	6
7	5	7	7
5	4	3	4
5	3	6	6
6	3	4	5
5	6	5	6
6	2	4	4
6	4	4	5
6	4	5	5
5	4	5	5
6	5	6	6
7	3	7	7
7	5	6	7
6	4	5	6
6	4	5	6
6	6	6	5
7	7	6	7
6	5	5	7
5	4	3	6
5	3	4	4
5	1	5	5




Summary of computational transaction
Raw Inputview raw input (R code)
Raw Outputview raw output of R engine
Computing time1 seconds
R Server'RServer@AstonUniversity' @ vre.aston.ac.uk

\begin{tabular}{lllllllll}
\hline
Summary of computational transaction \tabularnewline
Raw Input & view raw input (R code)  \tabularnewline
Raw Output & view raw output of R engine  \tabularnewline
Computing time & 1 seconds \tabularnewline
R Server & 'RServer@AstonUniversity' @ vre.aston.ac.uk \tabularnewline
\hline
\end{tabular}
%Source: https://freestatistics.org/blog/index.php?pk=86538&T=0

[TABLE]
[ROW][C]Summary of computational transaction[/C][/ROW]
[ROW][C]Raw Input[/C][C]view raw input (R code) [/C][/ROW]
[ROW][C]Raw Output[/C][C]view raw output of R engine [/C][/ROW]
[ROW][C]Computing time[/C][C]1 seconds[/C][/ROW]
[ROW][C]R Server[/C][C]'RServer@AstonUniversity' @ vre.aston.ac.uk[/C][/ROW]
[/TABLE]
Source: https://freestatistics.org/blog/index.php?pk=86538&T=0

Globally Unique Identifier (entire table): ba.freestatistics.org/blog/index.php?pk=86538&T=0

As an alternative you can also use a QR Code:  

The GUIDs for individual cells are displayed in the table below:

Summary of computational transaction
Raw Inputview raw input (R code)
Raw Outputview raw output of R engine
Computing time1 seconds
R Server'RServer@AstonUniversity' @ vre.aston.ac.uk







Summary of survey scores (median of Likert score was subtracted)
QuestionmeanSum ofpositives (Ps)Sum ofnegatives (Ns)(Ps-Ns)/(Ps+Ns)Count ofpositives (Pc)Count ofnegatives (Nc)(Pc-Nc)/(Pc+Nc)
11.8304130.92146100.87
20.38132700.3185430.33
30.86181410.63109270.6
41.52265190.87137120.84

\begin{tabular}{lllllllll}
\hline
Summary of survey scores (median of Likert score was subtracted) \tabularnewline
Question & mean & Sum ofpositives (Ps) & Sum ofnegatives (Ns) & (Ps-Ns)/(Ps+Ns) & Count ofpositives (Pc) & Count ofnegatives (Nc) & (Pc-Nc)/(Pc+Nc) \tabularnewline
1 & 1.8 & 304 & 13 & 0.92 & 146 & 10 & 0.87 \tabularnewline
2 & 0.38 & 132 & 70 & 0.31 & 85 & 43 & 0.33 \tabularnewline
3 & 0.86 & 181 & 41 & 0.63 & 109 & 27 & 0.6 \tabularnewline
4 & 1.52 & 265 & 19 & 0.87 & 137 & 12 & 0.84 \tabularnewline
\hline
\end{tabular}
%Source: https://freestatistics.org/blog/index.php?pk=86538&T=1

[TABLE]
[ROW][C]Summary of survey scores (median of Likert score was subtracted)[/C][/ROW]
[ROW][C]Question[/C][C]mean[/C][C]Sum ofpositives (Ps)[/C][C]Sum ofnegatives (Ns)[/C][C](Ps-Ns)/(Ps+Ns)[/C][C]Count ofpositives (Pc)[/C][C]Count ofnegatives (Nc)[/C][C](Pc-Nc)/(Pc+Nc)[/C][/ROW]
[ROW][C]1[/C][C]1.8[/C][C]304[/C][C]13[/C][C]0.92[/C][C]146[/C][C]10[/C][C]0.87[/C][/ROW]
[ROW][C]2[/C][C]0.38[/C][C]132[/C][C]70[/C][C]0.31[/C][C]85[/C][C]43[/C][C]0.33[/C][/ROW]
[ROW][C]3[/C][C]0.86[/C][C]181[/C][C]41[/C][C]0.63[/C][C]109[/C][C]27[/C][C]0.6[/C][/ROW]
[ROW][C]4[/C][C]1.52[/C][C]265[/C][C]19[/C][C]0.87[/C][C]137[/C][C]12[/C][C]0.84[/C][/ROW]
[/TABLE]
Source: https://freestatistics.org/blog/index.php?pk=86538&T=1

Globally Unique Identifier (entire table): ba.freestatistics.org/blog/index.php?pk=86538&T=1

As an alternative you can also use a QR Code:  

The GUIDs for individual cells are displayed in the table below:

Summary of survey scores (median of Likert score was subtracted)
QuestionmeanSum ofpositives (Ps)Sum ofnegatives (Ns)(Ps-Ns)/(Ps+Ns)Count ofpositives (Pc)Count ofnegatives (Nc)(Pc-Nc)/(Pc+Nc)
11.8304130.92146100.87
20.38132700.3185430.33
30.86181410.63109270.6
41.52265190.87137120.84







Pearson correlations of survey scores (and p-values)
mean(Ps-Ns)/(Ps+Ns)(Pc-Nc)/(Pc+Nc)
mean1 (0)0.98 (0.02)0.982 (0.018)
(Ps-Ns)/(Ps+Ns)0.98 (0.02)1 (0)0.999 (0.001)
(Pc-Nc)/(Pc+Nc)0.982 (0.018)0.999 (0.001)1 (0)

\begin{tabular}{lllllllll}
\hline
Pearson correlations of survey scores (and p-values) \tabularnewline
 & mean & (Ps-Ns)/(Ps+Ns) & (Pc-Nc)/(Pc+Nc) \tabularnewline
mean & 1 (0) & 0.98 (0.02) & 0.982 (0.018) \tabularnewline
(Ps-Ns)/(Ps+Ns) & 0.98 (0.02) & 1 (0) & 0.999 (0.001) \tabularnewline
(Pc-Nc)/(Pc+Nc) & 0.982 (0.018) & 0.999 (0.001) & 1 (0) \tabularnewline
\hline
\end{tabular}
%Source: https://freestatistics.org/blog/index.php?pk=86538&T=2

[TABLE]
[ROW][C]Pearson correlations of survey scores (and p-values)[/C][/ROW]
[ROW][C][/C][C]mean[/C][C](Ps-Ns)/(Ps+Ns)[/C][C](Pc-Nc)/(Pc+Nc)[/C][/ROW]
[ROW][C]mean[/C][C]1 (0)[/C][C]0.98 (0.02)[/C][C]0.982 (0.018)[/C][/ROW]
[ROW][C](Ps-Ns)/(Ps+Ns)[/C][C]0.98 (0.02)[/C][C]1 (0)[/C][C]0.999 (0.001)[/C][/ROW]
[ROW][C](Pc-Nc)/(Pc+Nc)[/C][C]0.982 (0.018)[/C][C]0.999 (0.001)[/C][C]1 (0)[/C][/ROW]
[/TABLE]
Source: https://freestatistics.org/blog/index.php?pk=86538&T=2

Globally Unique Identifier (entire table): ba.freestatistics.org/blog/index.php?pk=86538&T=2

As an alternative you can also use a QR Code:  

The GUIDs for individual cells are displayed in the table below:

Pearson correlations of survey scores (and p-values)
mean(Ps-Ns)/(Ps+Ns)(Pc-Nc)/(Pc+Nc)
mean1 (0)0.98 (0.02)0.982 (0.018)
(Ps-Ns)/(Ps+Ns)0.98 (0.02)1 (0)0.999 (0.001)
(Pc-Nc)/(Pc+Nc)0.982 (0.018)0.999 (0.001)1 (0)







Kendall tau rank correlations of survey scores (and p-values)
mean(Ps-Ns)/(Ps+Ns)(Pc-Nc)/(Pc+Nc)
mean1 (0.083)1 (0.083)1 (0.083)
(Ps-Ns)/(Ps+Ns)1 (0.083)1 (0.083)1 (0.083)
(Pc-Nc)/(Pc+Nc)1 (0.083)1 (0.083)1 (0.083)

\begin{tabular}{lllllllll}
\hline
Kendall tau rank correlations of survey scores (and p-values) \tabularnewline
 & mean & (Ps-Ns)/(Ps+Ns) & (Pc-Nc)/(Pc+Nc) \tabularnewline
mean & 1 (0.083) & 1 (0.083) & 1 (0.083) \tabularnewline
(Ps-Ns)/(Ps+Ns) & 1 (0.083) & 1 (0.083) & 1 (0.083) \tabularnewline
(Pc-Nc)/(Pc+Nc) & 1 (0.083) & 1 (0.083) & 1 (0.083) \tabularnewline
\hline
\end{tabular}
%Source: https://freestatistics.org/blog/index.php?pk=86538&T=3

[TABLE]
[ROW][C]Kendall tau rank correlations of survey scores (and p-values)[/C][/ROW]
[ROW][C][/C][C]mean[/C][C](Ps-Ns)/(Ps+Ns)[/C][C](Pc-Nc)/(Pc+Nc)[/C][/ROW]
[ROW][C]mean[/C][C]1 (0.083)[/C][C]1 (0.083)[/C][C]1 (0.083)[/C][/ROW]
[ROW][C](Ps-Ns)/(Ps+Ns)[/C][C]1 (0.083)[/C][C]1 (0.083)[/C][C]1 (0.083)[/C][/ROW]
[ROW][C](Pc-Nc)/(Pc+Nc)[/C][C]1 (0.083)[/C][C]1 (0.083)[/C][C]1 (0.083)[/C][/ROW]
[/TABLE]
Source: https://freestatistics.org/blog/index.php?pk=86538&T=3

Globally Unique Identifier (entire table): ba.freestatistics.org/blog/index.php?pk=86538&T=3

As an alternative you can also use a QR Code:  

The GUIDs for individual cells are displayed in the table below:

Kendall tau rank correlations of survey scores (and p-values)
mean(Ps-Ns)/(Ps+Ns)(Pc-Nc)/(Pc+Nc)
mean1 (0.083)1 (0.083)1 (0.083)
(Ps-Ns)/(Ps+Ns)1 (0.083)1 (0.083)1 (0.083)
(Pc-Nc)/(Pc+Nc)1 (0.083)1 (0.083)1 (0.083)



Parameters (Session):
par1 = 1 2 3 4 5 6 7 ;
Parameters (R input):
par1 = 1 2 3 4 5 6 7 ;
R code (references can be found in the software module):
docor <- function(x,y,method) {
r <- cor.test(x,y,method=method)
paste(round(r$estimate,3),' (',round(r$p.value,3),')',sep='')
}
x <- t(x)
nx <- length(x[,1])
cx <- length(x[1,])
mymedian <- median(as.numeric(strsplit(par1,' ')[[1]]))
myresult <- array(NA, dim = c(cx,7))
rownames(myresult) <- paste('Q',1:cx,sep='')
colnames(myresult) <- c('mean','Sum of
positives (Ps)','Sum of
negatives (Ns)', '(Ps-Ns)/(Ps+Ns)', 'Count of
positives (Pc)', 'Count of
negatives (Nc)', '(Pc-Nc)/(Pc+Nc)')
for (i in 1:cx) {
spos <- 0
sneg <- 0
cpos <- 0
cneg <- 0
for (j in 1:nx) {
if (!is.na(x[j,i])) {
myx <- as.numeric(x[j,i]) - mymedian
if (myx > 0) {
spos = spos + myx
cpos = cpos + 1
}
if (myx < 0) {
sneg = sneg + abs(myx)
cneg = cneg + 1
}
}
}
myresult[i,1] <- round(mean(as.numeric(x[,i]),na.rm=T)-mymedian,2)
myresult[i,2] <- spos
myresult[i,3] <- sneg
myresult[i,4] <- round((spos - sneg) / (spos + sneg),2)
myresult[i,5] <- cpos
myresult[i,6] <- cneg
myresult[i,7] <- round((cpos - cneg) / (cpos + cneg),2)
}
myresult
load(file='createtable')
a<-table.start()
a<-table.row.start(a)
a<-table.element(a,'Summary of survey scores (median of Likert score was subtracted)',8,TRUE)
a<-table.row.end(a)
a<-table.row.start(a)
a<-table.element(a,'Question',header=TRUE)
for (i in 1:7) {
a<-table.element(a,colnames(myresult)[i],header=TRUE)
}
a<-table.row.end(a)
for (i in 1:cx) {
a<-table.row.start(a)
a<-table.element(a,i,header=TRUE)
for (j in 1:7) {
a<-table.element(a,myresult[i,j],align='right')
}
a<-table.row.end(a)
}
a<-table.end(a)
table.save(a,file='mytable.tab')
a<-table.start()
a<-table.row.start(a)
a<-table.element(a,'Pearson correlations of survey scores (and p-values)',4,TRUE)
a<-table.row.end(a)
a<-table.row.start(a)
a<-table.element(a,'',header=TRUE)
a<-table.element(a,'mean',header=TRUE)
a<-table.element(a,'(Ps-Ns)/(Ps+Ns)',header=TRUE)
a<-table.element(a,'(Pc-Nc)/(Pc+Nc)',header=TRUE)
a<-table.row.end(a)
a<-table.row.start(a)
a<-table.element(a,'mean',header=TRUE)
a<-table.element(a,docor(myresult[,1],myresult[,1],method='pearson'),align='right')
a<-table.element(a,docor(myresult[,1],myresult[,4],method='pearson'),align='right')
a<-table.element(a,docor(myresult[,1],myresult[,7],method='pearson'),align='right')
a<-table.row.end(a)
a<-table.row.start(a)
a<-table.element(a,'(Ps-Ns)/(Ps+Ns)',header=TRUE)
a<-table.element(a,docor(myresult[,4],myresult[,1],method='pearson'),align='right')
a<-table.element(a,docor(myresult[,4],myresult[,4],method='pearson'),align='right')
a<-table.element(a,docor(myresult[,4],myresult[,7],method='pearson'),align='right')
a<-table.row.end(a)
a<-table.row.start(a)
a<-table.element(a,'(Pc-Nc)/(Pc+Nc)',header=TRUE)
a<-table.element(a,docor(myresult[,7],myresult[,1],method='pearson'),align='right')
a<-table.element(a,docor(myresult[,7],myresult[,4],method='pearson'),align='right')
a<-table.element(a,docor(myresult[,7],myresult[,7],method='pearson'),align='right')
a<-table.row.end(a)
a<-table.end(a)
table.save(a,file='mytable1.tab')
a<-table.start()
a<-table.row.start(a)
a<-table.element(a,'Kendall tau rank correlations of survey scores (and p-values)',4,TRUE)
a<-table.row.end(a)
a<-table.row.start(a)
a<-table.element(a,'',header=TRUE)
a<-table.element(a,'mean',header=TRUE)
a<-table.element(a,'(Ps-Ns)/(Ps+Ns)',header=TRUE)
a<-table.element(a,'(Pc-Nc)/(Pc+Nc)',header=TRUE)
a<-table.row.end(a)
a<-table.row.start(a)
a<-table.element(a,'mean',header=TRUE)
a<-table.element(a,docor(myresult[,1],myresult[,1],method='kendall'),align='right')
a<-table.element(a,docor(myresult[,1],myresult[,4],method='kendall'),align='right')
a<-table.element(a,docor(myresult[,1],myresult[,7],method='kendall'),align='right')
a<-table.row.end(a)
a<-table.row.start(a)
a<-table.element(a,'(Ps-Ns)/(Ps+Ns)',header=TRUE)
a<-table.element(a,docor(myresult[,4],myresult[,1],method='kendall'),align='right')
a<-table.element(a,docor(myresult[,4],myresult[,4],method='kendall'),align='right')
a<-table.element(a,docor(myresult[,4],myresult[,7],method='kendall'),align='right')
a<-table.row.end(a)
a<-table.row.start(a)
a<-table.element(a,'(Pc-Nc)/(Pc+Nc)',header=TRUE)
a<-table.element(a,docor(myresult[,7],myresult[,1],method='kendall'),align='right')
a<-table.element(a,docor(myresult[,7],myresult[,4],method='kendall'),align='right')
a<-table.element(a,docor(myresult[,7],myresult[,7],method='kendall'),align='right')
a<-table.row.end(a)
a<-table.end(a)
table.save(a,file='mytable2.tab')