Free Statistics

of Irreproducible Research!

Author's title

Author*The author of this computation has been verified*
R Software Modulerwasp_surveyscores.wasp
Title produced by softwareSurvey Scores
Date of computationMon, 18 Oct 2010 16:35:29 +0000
Cite this page as followsStatistical Computations at FreeStatistics.org, Office for Research Development and Education, URL https://freestatistics.org/blog/index.php?v=date/2010/Oct/18/t1287419678qfq2f1y6jqidvol.htm/, Retrieved Sat, 04 May 2024 18:21:48 +0000
Statistical Computations at FreeStatistics.org, Office for Research Development and Education, URL https://freestatistics.org/blog/index.php?pk=84984, Retrieved Sat, 04 May 2024 18:21:48 +0000
QR Codes:

Original text written by user:
IsPrivate?No (this computation is public)
User-defined keywords
Estimated Impact130
Family? (F = Feedback message, R = changed R code, M = changed R Module, P = changed Parameters, D = changed Data)
-     [Survey Scores] [Intrinsic Motivat...] [2010-10-12 11:18:40] [b98453cac15ba1066b407e146608df68]
F   PD    [Survey Scores] [] [2010-10-18 16:35:29] [6fde1c772c7be11768d9b6a0344566b2] [Current]
Feedback Forum
2010-10-23 13:00:07 [48eb36e2c01435ad7e4ea7854a9d98fe] [reply
Men kan hier vaststellen dat de Pearson correlatie erg hoog is. Hieruit kan men dus besluiten dat men kan werken met het rekenkundig gemiddelde.

Naast deze Pearson correlatie zou men zich ook kunnen baseren op de rangcorrelatie (dit is de tweede tabel). Hierbij gaat men voor elke maatstaf (mean, (Ps-Ns)/(Ps+Ns) en (Pc-Nc)/(Pc+Nc)) de rangschikking van de vier vragen bepalen en deze rangschikking gaat men dan voor de drie maatstaven met elkaar vergelijken. Hiervan kan men dan ook de correlatie bepalen en die wordt weergegeven in de tabel van de rangcorrelatie.

Post a new message
Dataseries X:
7	7	4	5
6	6	6	6
6	6	5	5
5	6	4	5
6	6	6	6
7	7	6	7
7	7	7	7
7	7	6	7
7	6	5	6
6	6	5	6
4	7	7	6
6	7	7	7
6	7	7	7
7	7	7	7
6	7	7	7
6	6	6	5
4	7	6	7
7	7	7	7
7	7	7	6
6	7	6	6
3	5	5	6
7	4	7	6
5	6	5	4
7	7	7	7
6	7	6	7
5	7	6	5
5	7	6	5
6	6	2	6
5	2	2	2
6	6	5	7
6	7	6	6
5	6	6	6
4	4	4	6
5	5	4	6
4	5	5	6
6	6	6	6
6	7	5	5
7	6	6	6
7	7	7	7
7	6	7	6
7	7	5	7
5	6	6	6
6	5	5	6
6	6	6	6
3	7	5	6
6	5	4	5
5	6	5	6
4	5	6	5
6	6	6	7
6	6	3	5
6	6	4	6
5	7	6	5
6	6	6	7
5	6	5	7
7	5	5	6
6	5	5	6
6	6	6	6
7	7	6	5
4	5	6	6
3	4	4	1
4	6	3	4
4	6	5	5
5	7	5	6
4	5	7	7
6	5	5	4
7	7	7	7
6	6	6	6
6	7	6	5
6	6	6	6
6	6	6	6
7	7	7	7
6	7	6	6
6	6	5	4
6	6	7	6
7	6	6	6
5	4	4	5
4	4	4	5
7	7	6	6
7	7	7	7
6	4	6	5
7	7	6	7
6	6	5	5
5	6	5	5
7	6	5	7
6	6	5	5
5	7	6	5
6	6	7	7
5	4	5	5
7	7	7	4
6	6	3	6
2	2	4	5
5	6	6	7
7	6	7	5
7	6	7	6
7	6	6	6
7	7	7	4
6	6	4	6
5	6	5	5
6	6	5	6
6	6	7	6
5	7	6	6
7	7	3	4
5	5	5	6
6	6	6	7
5	7	5	5
5	5	5	5
5	5	5	5
5	6	5	7
7	7	7	7
6	6	6	5
7	7	7	7
6	6	6	6
5	5	4	4
5	5	5	5
7	7	7	7
6	5	5	5
5	6	6	4
7	7	5	6
4	6	2	7
3	6	4	5
7	4	5	5
5	6	5	6
6	5	6	7
4	4	4	3
7	7	7	7
7	7	6	6
5	6	6	6
7	7	6	6
3	6	5	6
6	5	5	6
5	5	5	5
5	6	6	6
6	6	4	6
5	7	6	6
6	6	5	6
6	5	5	6
7	7	5	7
5	5	6	7
7	7	7	6
6	5	6	6
6	5	5	5
7	7	6	6
7	4	6	6
5	6	4	6
7	7	6	7
5	5	4	5
6	5	6	6
7	6	6	6
6	5	6	6
5	6	5	6
6	7	5	4
7	7	5	6
6	7	6	6
7	7	7	7
7	7	7	7
6	4	4	6
6	7	6	6
4	7	4	4
7	6	7	5
6	6	4	6
4	5	4	5
5	5	5	5




Summary of computational transaction
Raw Inputview raw input (R code)
Raw Outputview raw output of R engine
Computing time1 seconds
R Server'Gwilym Jenkins' @ 72.249.127.135

\begin{tabular}{lllllllll}
\hline
Summary of computational transaction \tabularnewline
Raw Input & view raw input (R code)  \tabularnewline
Raw Output & view raw output of R engine  \tabularnewline
Computing time & 1 seconds \tabularnewline
R Server & 'Gwilym Jenkins' @ 72.249.127.135 \tabularnewline
\hline
\end{tabular}
%Source: https://freestatistics.org/blog/index.php?pk=84984&T=0

[TABLE]
[ROW][C]Summary of computational transaction[/C][/ROW]
[ROW][C]Raw Input[/C][C]view raw input (R code) [/C][/ROW]
[ROW][C]Raw Output[/C][C]view raw output of R engine [/C][/ROW]
[ROW][C]Computing time[/C][C]1 seconds[/C][/ROW]
[ROW][C]R Server[/C][C]'Gwilym Jenkins' @ 72.249.127.135[/C][/ROW]
[/TABLE]
Source: https://freestatistics.org/blog/index.php?pk=84984&T=0

Globally Unique Identifier (entire table): ba.freestatistics.org/blog/index.php?pk=84984&T=0

As an alternative you can also use a QR Code:  

The GUIDs for individual cells are displayed in the table below:

Summary of computational transaction
Raw Inputview raw input (R code)
Raw Outputview raw output of R engine
Computing time1 seconds
R Server'Gwilym Jenkins' @ 72.249.127.135







Summary of survey scores (median of Likert score was subtracted)
QuestionmeanSum ofpositives (Ps)Sum ofnegatives (Ns)(Ps-Ns)/(Ps+Ns)Count ofpositives (Pc)Count ofnegatives (Nc)(Pc-Nc)/(Pc+Nc)
11.7729470.9514260.92
21.9932640.9814920.97
31.49252100.9213470.9
41.7829560.9614830.96

\begin{tabular}{lllllllll}
\hline
Summary of survey scores (median of Likert score was subtracted) \tabularnewline
Question & mean & Sum ofpositives (Ps) & Sum ofnegatives (Ns) & (Ps-Ns)/(Ps+Ns) & Count ofpositives (Pc) & Count ofnegatives (Nc) & (Pc-Nc)/(Pc+Nc) \tabularnewline
1 & 1.77 & 294 & 7 & 0.95 & 142 & 6 & 0.92 \tabularnewline
2 & 1.99 & 326 & 4 & 0.98 & 149 & 2 & 0.97 \tabularnewline
3 & 1.49 & 252 & 10 & 0.92 & 134 & 7 & 0.9 \tabularnewline
4 & 1.78 & 295 & 6 & 0.96 & 148 & 3 & 0.96 \tabularnewline
\hline
\end{tabular}
%Source: https://freestatistics.org/blog/index.php?pk=84984&T=1

[TABLE]
[ROW][C]Summary of survey scores (median of Likert score was subtracted)[/C][/ROW]
[ROW][C]Question[/C][C]mean[/C][C]Sum ofpositives (Ps)[/C][C]Sum ofnegatives (Ns)[/C][C](Ps-Ns)/(Ps+Ns)[/C][C]Count ofpositives (Pc)[/C][C]Count ofnegatives (Nc)[/C][C](Pc-Nc)/(Pc+Nc)[/C][/ROW]
[ROW][C]1[/C][C]1.77[/C][C]294[/C][C]7[/C][C]0.95[/C][C]142[/C][C]6[/C][C]0.92[/C][/ROW]
[ROW][C]2[/C][C]1.99[/C][C]326[/C][C]4[/C][C]0.98[/C][C]149[/C][C]2[/C][C]0.97[/C][/ROW]
[ROW][C]3[/C][C]1.49[/C][C]252[/C][C]10[/C][C]0.92[/C][C]134[/C][C]7[/C][C]0.9[/C][/ROW]
[ROW][C]4[/C][C]1.78[/C][C]295[/C][C]6[/C][C]0.96[/C][C]148[/C][C]3[/C][C]0.96[/C][/ROW]
[/TABLE]
Source: https://freestatistics.org/blog/index.php?pk=84984&T=1

Globally Unique Identifier (entire table): ba.freestatistics.org/blog/index.php?pk=84984&T=1

As an alternative you can also use a QR Code:  

The GUIDs for individual cells are displayed in the table below:

Summary of survey scores (median of Likert score was subtracted)
QuestionmeanSum ofpositives (Ps)Sum ofnegatives (Ns)(Ps-Ns)/(Ps+Ns)Count ofpositives (Pc)Count ofnegatives (Nc)(Pc-Nc)/(Pc+Nc)
11.7729470.9514260.92
21.9932640.9814920.97
31.49252100.9213470.9
41.7829560.9614830.96







Pearson correlations of survey scores (and p-values)
mean(Ps-Ns)/(Ps+Ns)(Pc-Nc)/(Pc+Nc)
mean1 (0)0.989 (0.011)0.879 (0.121)
(Ps-Ns)/(Ps+Ns)0.989 (0.011)1 (0)0.938 (0.062)
(Pc-Nc)/(Pc+Nc)0.879 (0.121)0.938 (0.062)1 (0)

\begin{tabular}{lllllllll}
\hline
Pearson correlations of survey scores (and p-values) \tabularnewline
 & mean & (Ps-Ns)/(Ps+Ns) & (Pc-Nc)/(Pc+Nc) \tabularnewline
mean & 1 (0) & 0.989 (0.011) & 0.879 (0.121) \tabularnewline
(Ps-Ns)/(Ps+Ns) & 0.989 (0.011) & 1 (0) & 0.938 (0.062) \tabularnewline
(Pc-Nc)/(Pc+Nc) & 0.879 (0.121) & 0.938 (0.062) & 1 (0) \tabularnewline
\hline
\end{tabular}
%Source: https://freestatistics.org/blog/index.php?pk=84984&T=2

[TABLE]
[ROW][C]Pearson correlations of survey scores (and p-values)[/C][/ROW]
[ROW][C][/C][C]mean[/C][C](Ps-Ns)/(Ps+Ns)[/C][C](Pc-Nc)/(Pc+Nc)[/C][/ROW]
[ROW][C]mean[/C][C]1 (0)[/C][C]0.989 (0.011)[/C][C]0.879 (0.121)[/C][/ROW]
[ROW][C](Ps-Ns)/(Ps+Ns)[/C][C]0.989 (0.011)[/C][C]1 (0)[/C][C]0.938 (0.062)[/C][/ROW]
[ROW][C](Pc-Nc)/(Pc+Nc)[/C][C]0.879 (0.121)[/C][C]0.938 (0.062)[/C][C]1 (0)[/C][/ROW]
[/TABLE]
Source: https://freestatistics.org/blog/index.php?pk=84984&T=2

Globally Unique Identifier (entire table): ba.freestatistics.org/blog/index.php?pk=84984&T=2

As an alternative you can also use a QR Code:  

The GUIDs for individual cells are displayed in the table below:

Pearson correlations of survey scores (and p-values)
mean(Ps-Ns)/(Ps+Ns)(Pc-Nc)/(Pc+Nc)
mean1 (0)0.989 (0.011)0.879 (0.121)
(Ps-Ns)/(Ps+Ns)0.989 (0.011)1 (0)0.938 (0.062)
(Pc-Nc)/(Pc+Nc)0.879 (0.121)0.938 (0.062)1 (0)







Kendall tau rank correlations of survey scores (and p-values)
mean(Ps-Ns)/(Ps+Ns)(Pc-Nc)/(Pc+Nc)
mean1 (0.083)1 (0.083)1 (0.083)
(Ps-Ns)/(Ps+Ns)1 (0.083)1 (0.083)1 (0.083)
(Pc-Nc)/(Pc+Nc)1 (0.083)1 (0.083)1 (0.083)

\begin{tabular}{lllllllll}
\hline
Kendall tau rank correlations of survey scores (and p-values) \tabularnewline
 & mean & (Ps-Ns)/(Ps+Ns) & (Pc-Nc)/(Pc+Nc) \tabularnewline
mean & 1 (0.083) & 1 (0.083) & 1 (0.083) \tabularnewline
(Ps-Ns)/(Ps+Ns) & 1 (0.083) & 1 (0.083) & 1 (0.083) \tabularnewline
(Pc-Nc)/(Pc+Nc) & 1 (0.083) & 1 (0.083) & 1 (0.083) \tabularnewline
\hline
\end{tabular}
%Source: https://freestatistics.org/blog/index.php?pk=84984&T=3

[TABLE]
[ROW][C]Kendall tau rank correlations of survey scores (and p-values)[/C][/ROW]
[ROW][C][/C][C]mean[/C][C](Ps-Ns)/(Ps+Ns)[/C][C](Pc-Nc)/(Pc+Nc)[/C][/ROW]
[ROW][C]mean[/C][C]1 (0.083)[/C][C]1 (0.083)[/C][C]1 (0.083)[/C][/ROW]
[ROW][C](Ps-Ns)/(Ps+Ns)[/C][C]1 (0.083)[/C][C]1 (0.083)[/C][C]1 (0.083)[/C][/ROW]
[ROW][C](Pc-Nc)/(Pc+Nc)[/C][C]1 (0.083)[/C][C]1 (0.083)[/C][C]1 (0.083)[/C][/ROW]
[/TABLE]
Source: https://freestatistics.org/blog/index.php?pk=84984&T=3

Globally Unique Identifier (entire table): ba.freestatistics.org/blog/index.php?pk=84984&T=3

As an alternative you can also use a QR Code:  

The GUIDs for individual cells are displayed in the table below:

Kendall tau rank correlations of survey scores (and p-values)
mean(Ps-Ns)/(Ps+Ns)(Pc-Nc)/(Pc+Nc)
mean1 (0.083)1 (0.083)1 (0.083)
(Ps-Ns)/(Ps+Ns)1 (0.083)1 (0.083)1 (0.083)
(Pc-Nc)/(Pc+Nc)1 (0.083)1 (0.083)1 (0.083)



Parameters (Session):
par1 = 1 2 3 4 5 6 7 ;
Parameters (R input):
par1 = 1 2 3 4 5 6 7 ;
R code (references can be found in the software module):
docor <- function(x,y,method) {
r <- cor.test(x,y,method=method)
paste(round(r$estimate,3),' (',round(r$p.value,3),')',sep='')
}
x <- t(x)
nx <- length(x[,1])
cx <- length(x[1,])
mymedian <- median(as.numeric(strsplit(par1,' ')[[1]]))
myresult <- array(NA, dim = c(cx,7))
rownames(myresult) <- paste('Q',1:cx,sep='')
colnames(myresult) <- c('mean','Sum of
positives (Ps)','Sum of
negatives (Ns)', '(Ps-Ns)/(Ps+Ns)', 'Count of
positives (Pc)', 'Count of
negatives (Nc)', '(Pc-Nc)/(Pc+Nc)')
for (i in 1:cx) {
spos <- 0
sneg <- 0
cpos <- 0
cneg <- 0
for (j in 1:nx) {
if (!is.na(x[j,i])) {
myx <- as.numeric(x[j,i]) - mymedian
if (myx > 0) {
spos = spos + myx
cpos = cpos + 1
}
if (myx < 0) {
sneg = sneg + abs(myx)
cneg = cneg + 1
}
}
}
myresult[i,1] <- round(mean(as.numeric(x[,i]),na.rm=T)-mymedian,2)
myresult[i,2] <- spos
myresult[i,3] <- sneg
myresult[i,4] <- round((spos - sneg) / (spos + sneg),2)
myresult[i,5] <- cpos
myresult[i,6] <- cneg
myresult[i,7] <- round((cpos - cneg) / (cpos + cneg),2)
}
myresult
load(file='createtable')
a<-table.start()
a<-table.row.start(a)
a<-table.element(a,'Summary of survey scores (median of Likert score was subtracted)',8,TRUE)
a<-table.row.end(a)
a<-table.row.start(a)
a<-table.element(a,'Question',header=TRUE)
for (i in 1:7) {
a<-table.element(a,colnames(myresult)[i],header=TRUE)
}
a<-table.row.end(a)
for (i in 1:cx) {
a<-table.row.start(a)
a<-table.element(a,i,header=TRUE)
for (j in 1:7) {
a<-table.element(a,myresult[i,j],align='right')
}
a<-table.row.end(a)
}
a<-table.end(a)
table.save(a,file='mytable.tab')
a<-table.start()
a<-table.row.start(a)
a<-table.element(a,'Pearson correlations of survey scores (and p-values)',4,TRUE)
a<-table.row.end(a)
a<-table.row.start(a)
a<-table.element(a,'',header=TRUE)
a<-table.element(a,'mean',header=TRUE)
a<-table.element(a,'(Ps-Ns)/(Ps+Ns)',header=TRUE)
a<-table.element(a,'(Pc-Nc)/(Pc+Nc)',header=TRUE)
a<-table.row.end(a)
a<-table.row.start(a)
a<-table.element(a,'mean',header=TRUE)
a<-table.element(a,docor(myresult[,1],myresult[,1],method='pearson'),align='right')
a<-table.element(a,docor(myresult[,1],myresult[,4],method='pearson'),align='right')
a<-table.element(a,docor(myresult[,1],myresult[,7],method='pearson'),align='right')
a<-table.row.end(a)
a<-table.row.start(a)
a<-table.element(a,'(Ps-Ns)/(Ps+Ns)',header=TRUE)
a<-table.element(a,docor(myresult[,4],myresult[,1],method='pearson'),align='right')
a<-table.element(a,docor(myresult[,4],myresult[,4],method='pearson'),align='right')
a<-table.element(a,docor(myresult[,4],myresult[,7],method='pearson'),align='right')
a<-table.row.end(a)
a<-table.row.start(a)
a<-table.element(a,'(Pc-Nc)/(Pc+Nc)',header=TRUE)
a<-table.element(a,docor(myresult[,7],myresult[,1],method='pearson'),align='right')
a<-table.element(a,docor(myresult[,7],myresult[,4],method='pearson'),align='right')
a<-table.element(a,docor(myresult[,7],myresult[,7],method='pearson'),align='right')
a<-table.row.end(a)
a<-table.end(a)
table.save(a,file='mytable1.tab')
a<-table.start()
a<-table.row.start(a)
a<-table.element(a,'Kendall tau rank correlations of survey scores (and p-values)',4,TRUE)
a<-table.row.end(a)
a<-table.row.start(a)
a<-table.element(a,'',header=TRUE)
a<-table.element(a,'mean',header=TRUE)
a<-table.element(a,'(Ps-Ns)/(Ps+Ns)',header=TRUE)
a<-table.element(a,'(Pc-Nc)/(Pc+Nc)',header=TRUE)
a<-table.row.end(a)
a<-table.row.start(a)
a<-table.element(a,'mean',header=TRUE)
a<-table.element(a,docor(myresult[,1],myresult[,1],method='kendall'),align='right')
a<-table.element(a,docor(myresult[,1],myresult[,4],method='kendall'),align='right')
a<-table.element(a,docor(myresult[,1],myresult[,7],method='kendall'),align='right')
a<-table.row.end(a)
a<-table.row.start(a)
a<-table.element(a,'(Ps-Ns)/(Ps+Ns)',header=TRUE)
a<-table.element(a,docor(myresult[,4],myresult[,1],method='kendall'),align='right')
a<-table.element(a,docor(myresult[,4],myresult[,4],method='kendall'),align='right')
a<-table.element(a,docor(myresult[,4],myresult[,7],method='kendall'),align='right')
a<-table.row.end(a)
a<-table.row.start(a)
a<-table.element(a,'(Pc-Nc)/(Pc+Nc)',header=TRUE)
a<-table.element(a,docor(myresult[,7],myresult[,1],method='kendall'),align='right')
a<-table.element(a,docor(myresult[,7],myresult[,4],method='kendall'),align='right')
a<-table.element(a,docor(myresult[,7],myresult[,7],method='kendall'),align='right')
a<-table.row.end(a)
a<-table.end(a)
table.save(a,file='mytable2.tab')