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Author's title

Author*The author of this computation has been verified*
R Software Modulerwasp_rwalk.wasp
Title produced by softwareLaw of Averages
Date of computationMon, 01 Dec 2008 14:52:54 -0700
Cite this page as followsStatistical Computations at FreeStatistics.org, Office for Research Development and Education, URL https://freestatistics.org/blog/index.php?v=date/2008/Dec/01/t1228168482e4m6nldjb3h262y.htm/, Retrieved Sun, 05 May 2024 15:18:03 +0000
Statistical Computations at FreeStatistics.org, Office for Research Development and Education, URL https://freestatistics.org/blog/index.php?pk=27440, Retrieved Sun, 05 May 2024 15:18:03 +0000
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Original text written by user:
IsPrivate?No (this computation is public)
User-defined keywordsNon Stationary Time Series
Estimated Impact215
Family? (F = Feedback message, R = changed R code, M = changed R Module, P = changed Parameters, D = changed Data)
F     [Law of Averages] [Random Walk Simul...] [2008-11-25 17:50:19] [b98453cac15ba1066b407e146608df68]
F       [Law of Averages] [Repr 1] [2008-11-26 16:08:27] [8eb83367d7ce233bbf617141d324189b]
F           [Law of Averages] [question 1 Reprod...] [2008-12-01 21:52:54] [3efbb18563b4564408d69b3c9a8e9a6e] [Current]
Feedback Forum
2008-12-08 07:29:09 [0762c65deec3d397cd9f26b3749a0847] [reply
Er is 50/50 kans dat het kop of munt is als je werpt. in de 1e grafiek ‘Excess of heads’ laat zien hoeveel x er kop gegooid werd. Als er telkens om de beurt kop en munt gegooid werd dan zou de grafiek horizontaal lopen met een minimale spreiding. Alles hangt inderdaad af van het 'toeval'.
2008-12-09 07:27:09 [An De Koninck] [reply
Bij het gooien van een muntstuk is er inderdaad enkel het toeval dat speelt. Je hebt steeds 1 kans op 2 (= 50%) om kop of munt te gooien. Er is dus geen seizonaliteit op lange termijntrend die meespeelt.
De eerste grafiek geeft weer hoeveel er juist kop gegooid is. Dit wordt weergegeven op de y-as en op de x-as staat het aantal worpen weer.
Het Random Walk Model is Y(t)=Yt-1 +Ct. De uitslag van deze worp is dus afhankelijk van de uitslag van de vorige worp + het toeval.

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Summary of computational transaction
Raw Inputview raw input (R code)
Raw Outputview raw output of R engine
Computing time1 seconds
R Server'Gwilym Jenkins' @ 72.249.127.135

\begin{tabular}{lllllllll}
\hline
Summary of computational transaction \tabularnewline
Raw Input & view raw input (R code)  \tabularnewline
Raw Output & view raw output of R engine  \tabularnewline
Computing time & 1 seconds \tabularnewline
R Server & 'Gwilym Jenkins' @ 72.249.127.135 \tabularnewline
\hline
\end{tabular}
%Source: https://freestatistics.org/blog/index.php?pk=27440&T=0

[TABLE]
[ROW][C]Summary of computational transaction[/C][/ROW]
[ROW][C]Raw Input[/C][C]view raw input (R code) [/C][/ROW]
[ROW][C]Raw Output[/C][C]view raw output of R engine [/C][/ROW]
[ROW][C]Computing time[/C][C]1 seconds[/C][/ROW]
[ROW][C]R Server[/C][C]'Gwilym Jenkins' @ 72.249.127.135[/C][/ROW]
[/TABLE]
Source: https://freestatistics.org/blog/index.php?pk=27440&T=0

Globally Unique Identifier (entire table): ba.freestatistics.org/blog/index.php?pk=27440&T=0

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The GUIDs for individual cells are displayed in the table below:

Summary of computational transaction
Raw Inputview raw input (R code)
Raw Outputview raw output of R engine
Computing time1 seconds
R Server'Gwilym Jenkins' @ 72.249.127.135



Parameters (Session):
par1 = 500 ; par2 = 0.5 ;
Parameters (R input):
par1 = 500 ; par2 = 0.5 ; par3 = ; par4 = ; par5 = ; par6 = ; par7 = ; par8 = ; par9 = ; par10 = ; par11 = ; par12 = ; par13 = ; par14 = ; par15 = ; par16 = ; par17 = ; par18 = ; par19 = ; par20 = ;
R code (references can be found in the software module):
n <- as.numeric(par1)
p <- as.numeric(par2)
heads=rbinom(n-1,1,p)
a=2*(heads)-1
b=diffinv(a,xi=0)
c=1:n
pheads=(diffinv(heads,xi=.5))/c
bitmap(file='test1.png')
op=par(mfrow=c(2,1))
plot(c,b,type='n',main='Law of Averages',xlab='Toss Number',ylab='Excess of Heads',lwd=2,cex.lab=1.5,cex.main=2)
lines(c,b,col='red')
lines(c,rep(0,n),col='black')
plot(c,pheads,type='n',xlab='Toss Number',ylab='Proportion of Heads',lwd=2,cex.lab=1.5)
lines(c,pheads,col='blue')
lines(c,rep(.5,n),col='black')
par(op)
dev.off()